Решите, пожалуйста Номера 4 и 5!

32^(2/5) = (корень 5 )от числа 32² =(корень 5)  2^(5*2) =2^(2*5/5) =2² =4
* * *
32^(2/5) =(2^5)^(2/5)=(2)^(5*2/5) =2²=4.
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49^(3/2) =√(49³) =√(7²)³ =√(7^6) =7^(6/2) =7³=343.
* * *49^(3/2) =(7²)^(3/2) = 7^(2*3/2) =7³ =243 * * *
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100^0,5 =100^(1/2) =√100 =10.
* * * 1100^0,5 =(10²)^(1/2) =10^(2*1/2) =10.
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(Lq2+Lq50)/(2Lq1+Lq10) =Lq(2*50)/(2*0 +1) =Lq100 =Lq(10²) =2