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Решение
log₂ x + log₃ x = log₃6
log₃ x/log₃ 2 + log₃ x = log₃6
[log₃ x / log₃ 2)] * (1 + log₃ 2) = log₃ 2 + log₃ 3
[log₃ x / log₃ 2)] * (1 + log₃ 2) = 1 + log₃ 2
[log₃ x / log₃ 2)] = 1
log₃ x = log₃ 2
x = 2
log₂ x + log₃ x = log₃6
log₃ x/log₃ 2 + log₃ x = log₃6
[log₃ x / log₃ 2)] * (1 + log₃ 2) = log₃ 2 + log₃ 3
[log₃ x / log₃ 2)] * (1 + log₃ 2) = 1 + log₃ 2
[log₃ x / log₃ 2)] = 1
log₃ x = log₃ 2
x = 2
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