sin(2x+п/2)=1

cos(x/2-п/3)=0

Решение
1)  sin(2x + π/2) = 1
cos2x = 1
2x = 2πk, k∈Z
x = πk, k∈Z
2)  cos(x/2 - π/3) = 0
x/2 - π/3 = π/2 + πn, n∈Z
x/2 = π/2 +π/3 +  πn, n∈Z
x/2 = 5π/6 +  πn, n∈Z
x = 5π/3 +  2πn, n∈Z