помогите решит неравенства


1 (
2 log

1) (1/32)^(2x) >= sqrt(0.125)
0.5^(5*2x)>=0.5^(3/2)
10x <= 3/2
x<=3/20
x<=0.15
2) log(1/3, 5x-1) >=2
ОДЗ: 5x-1>0, x>0.2
log(1/3, 5x-1) >= log(1/3, 1/9)
5x-1 <= 1/9
x<=2/9
С учетом ОДЗ, 0.2 < x <= 2/9