Ответы
Ответ дал:
0
sinx+cosx=sinx+sinx(π/2-x)=2sinπ/4cos(x-π/4)=√2cos(x-π/4)
√2|cos(x-π/4)<√2/2
|cos(x-π/4)|<1/2
-1/2<cos(x-π/4)<1/2
π/3+2πn<x-π/4<2π/3+2πn U 4π/3+2πn<x-π/4<5π/3+2πn
7π/12+2πn<x<11π/12+2πn U 19π/12+2πn<23π/12+2πn,n∈z
√2|cos(x-π/4)<√2/2
|cos(x-π/4)|<1/2
-1/2<cos(x-π/4)<1/2
π/3+2πn<x-π/4<2π/3+2πn U 4π/3+2πn<x-π/4<5π/3+2πn
7π/12+2πn<x<11π/12+2πn U 19π/12+2πn<23π/12+2πn,n∈z
Похожие вопросы
2 года назад
7 лет назад
7 лет назад
9 лет назад
9 лет назад
10 лет назад
10 лет назад