Решите пожалуйста! (3х+4)в квадрате+3(х-2)=46

(3х+4)^2+3(х-2)=46

9x^2+24x+16+3x-6-46=0

9x^2+27x-36=0

D=27^2-4*9*(-36)

D=729+1296

D=2025

x1=1

x2=-4

(3x+4)^2+3(x-2)=46
9x^2+24x+16+3*(x-2)-46=0

9x^2+24x+16+3x-6-46=0

9x^2+27x+16-6-46=0

9x^2+27x+10-46=0

9x^2+27x-36=0

D=729+1296=2025

x1=(45-27)/(2*9)=18/18=1
x2=(-45-27)/(2*9)=-72/18=-4