ПОМОГИТЕ!!!!!!!!!!!!!!!!!!!!!!!!!!!!

 

4^x/4^x(2(5/2)^2x-(5/2)^x+1

(5/2)^x=t

f(t)=1/(2t^2-t+1)

f'(x)=-((4t-1)*(5/2)^xln(5/2))/(2t^2-t+1)^2

f'(x)=0

1-4t=0

t=1/4

2,5^x=0,25

x=log(5/2)1/4=ln1/4/ln(5/2)=-ln4/(ln5-ln2)~1,513

f(1/4)=1/(2*1/16-1/4+1)=1/(1/8-1/4+1)=1/(1-1/8)=8/7

max =8/7

x~-1,513