Ответы
Ответ дал:
0
Сразу разложу и сведу:
![frac{8 x^{2} y^{2}}{(x-y)(x+y)}: frac{x(x+y)-x(x-y)}{(x+y)(x-y)}= \ \
= frac{8 x^{2} y^{2}}{(x-y)(x+y)}: frac{x^{2}+xy-x^{2}+xy}{(x-y)(x+y)}=frac{8 x^{2} y^{2}}{(x-y)(x+y)}: frac{2xy}{(x-y)(x+y)}= \ \
=frac{8 x^{2} y^{2}}{(x-y)(x+y)}* frac{(x-y)(x+y)}{2xy} =4xy](https://tex.z-dn.net/?f=+frac%7B8+x%5E%7B2%7D+y%5E%7B2%7D%7D%7B%28x-y%29%28x%2By%29%7D%3A+frac%7Bx%28x%2By%29-x%28x-y%29%7D%7B%28x%2By%29%28x-y%29%7D%3D+%5C++%5C+%0A%3D++frac%7B8+x%5E%7B2%7D+y%5E%7B2%7D%7D%7B%28x-y%29%28x%2By%29%7D%3A+frac%7Bx%5E%7B2%7D%2Bxy-x%5E%7B2%7D%2Bxy%7D%7B%28x-y%29%28x%2By%29%7D%3Dfrac%7B8+x%5E%7B2%7D+y%5E%7B2%7D%7D%7B%28x-y%29%28x%2By%29%7D%3A++frac%7B2xy%7D%7B%28x-y%29%28x%2By%29%7D%3D+%5C++%5C+%0A%3Dfrac%7B8+x%5E%7B2%7D+y%5E%7B2%7D%7D%7B%28x-y%29%28x%2By%29%7D%2A+frac%7B%28x-y%29%28x%2By%29%7D%7B2xy%7D+%3D4xy "frac{8 x^{2} y^{2}}{(x-y)(x+y)}: frac{x(x+y)-x(x-y)}{(x+y)(x-y)}= \ \
= frac{8 x^{2} y^{2}}{(x-y)(x+y)}: frac{x^{2}+xy-x^{2}+xy}{(x-y)(x+y)}=frac{8 x^{2} y^{2}}{(x-y)(x+y)}: frac{2xy}{(x-y)(x+y)}= \ \
=frac{8 x^{2} y^{2}}{(x-y)(x+y)}* frac{(x-y)(x+y)}{2xy} =4xy")
Похожие вопросы
2 года назад
2 года назад
8 лет назад
8 лет назад