• Предмет: Математика
  • Автор: Akhmed28
  • Вопрос задан 7 лет назад

ПОМОГИТЕ ПОЖАЛУЙСТА

Приложения:

Ответы

Ответ дал: snow99
0
1)
x + y = 7 \ xy = 12 \  \ y = 7 - x \ x(7 - x) = 12 \  \ y = 7 - x \ 7x -  {x}^{2}  = 12 \  \ y = 7 - x \  {x}^{2}  - 7x + 12 = 0 \ x1 = 4 \ x2 = 3 \  y1 = 3 \ y2 = 4
(x + y) = 7
Ответ: 7.

2)
 {y}^{2}  +  {x}^{2}  = 17 \ y - 3x - 1 = 0 \  \ y = 3x + 1 \ (3x + 1) ^{2}  +  {x}^{2}  = 17 \  \ y = 3x + 1 \ 9 {x}^{2}  + 6x + 1 +  {x}^{2}  = 17 \  \ y = 3x + 1 \ 10 {x}^{2}  + 6x - 16 = 0 \   \ y = 3x + 1 \ 5 {x}^{2}  + 3x - 8 = 0 \   d =  {b}^{2}  - 4ac = 9 - 4 times 5 times ( - 8) = 169 \  x1 =  frac{ - 3 + 13}{10}  = 1 \ x2 =  frac{ - 3 - 13}{10}  =  -  frac{8}{5}  \ y1 = 4 \ y2 = 3 times ( -  frac{8}{5} ) + 1 =  -  frac{24}{5}  +  frac{5}{5}  =  -  frac{19}{5}  \ x1 + y1 = 5 \ x2 + y2 =  -  frac{27}{5}
Ответ: 5.

3)
x - y = 4 \ xy = 5 \  \ x = 4 + y \ y(4 + y) = 5 \  \ x = 4 + y \  {y}^{2}  + 4y - 5 = 0 \  \ x = 4 + y \ y1 =  - 5 \ y2 =  1 \ x1 =  - 1 \ x2 = 5 \ x1 + y1 =  - 6 \ x2 + y2 = 6
Ответ: 6.

4)
 {x}^{2}  +  {y}^{2}  = 10 \ x - y = 2 \  \ x = 2 + y \  {(2 + y)}^{2}  +  {y}^{2}  = 10 \  \ x = 2 + y \ 4 + 4y +  {y}^{2}  +  {y}^{2}  = 10 \  \ x = 2 + y \ 2 {y}^{2}  + 4y - 6 = 0 \  \ x = 2 + y \  {y}^{2}  + 2y - 3 = 0 \  \ x = 2 + y \ y1 =  - 3 \ y2 = 1 \ x1 =  - 1 \ x2 = 3 \ x1 + y1 =  - 4 \ x2 + y2 = 4
Ответ: 4.
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