Решите 14у+2у(6-у)=16у.6у

14у+2у(6-у)=16у*6у;

14y+12y-2y^2=96y^2;

26y-2y^2=96^2; ( делим обе части на 2 )

13y-y^2=48y^2;

13y-y^2-48y^2=0 ;

13y-49y^2=0;

y=0

или

13-49y=0;

13=49y;

y=13/49;

Ответ : y1=0 , y2=13/49

               

14y + 2y (6-y) = 16y,6y
7y + y * (6-y) = 4,8y^2
7y + 6y - y^2 = 24/5 y^2
13y-y^2 = 24/5 y^2
65y - 5y^2 = 24y^2
65y - 5y^2 - 24y^2 = 0
65y - 29y^2 = 0
y*(65-29y) = 0
y=0
65-29y=0
y=0
y= 65/29

y1=0
y2=65/29