Помогите пожалуйста)​

log(a^x) b^y = y/x log(a) b

log(√2 + 1)(3 + 2√2) = log(√2 + 1)(√2² + 2√2 +1) = log(√2 + 1)(1 + √2)² = 2

log (2) 1/16 = log(2) 2^-4 = -4

log(1/3) ⁵√81 = - log(3) 3^⁴/⁵ = - 4/5

log(√2 + 1)(3 + 2√2) - log² (1/3) ⁵√81 + log (2) 1/16= 2 - (-4/5)² + (-4) = -2 - 16/25 = -2 16/25 = -2.64