(x^2-5x+7)^2-(x-2)(x-3)=1
Пожалуйста помогите)))

(x^2 - 5x + 7)^2 = 1 + (x - 2)(x - 3)
(x^2 - 5x + 7)^2 = 1 + x^2 - 5x + 6
(x^2 - 5x +7)^2 = x^2 - 5x + 7
x^2 - 5x + 7 = 1
x^2 - 5x + 6 = 0
d = 25 - 24 = 1
X1 = 2
X2 = 3