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Метод интервалов:
![(4 x^{2} -9)(25- x^{2} )(3 x^{2} +2)>0 \
(2 x -3)(2x+3)(5-x )(5+x)(3 x^{2} +2)>0 \ x_1=3/2; x_2=-3/2; x_3=5; x_4=-5; 3 x^{2} +2 neq 0 \
x in (-5;-3/2) cup (3/2;5)](https://tex.z-dn.net/?f=%284+x%5E%7B2%7D+-9%29%2825-+x%5E%7B2%7D+%29%283+x%5E%7B2%7D+%2B2%29%26gt%3B0+%5C+%0A%282+x+-3%29%282x%2B3%29%285-x+%29%285%2Bx%29%283+x%5E%7B2%7D+%2B2%29%26gt%3B0+%5C+x_1%3D3%2F2%3B++x_2%3D-3%2F2%3B++x_3%3D5%3B++x_4%3D-5%3B++3+x%5E%7B2%7D+%2B2+neq+0+%5C+%0Ax+in+%28-5%3B-3%2F2%29+cup+%283%2F2%3B5%29 "(4 x^{2} -9)(25- x^{2} )(3 x^{2} +2)>0 \
(2 x -3)(2x+3)(5-x )(5+x)(3 x^{2} +2)>0 \ x_1=3/2; x_2=-3/2; x_3=5; x_4=-5; 3 x^{2} +2 neq 0 \
x in (-5;-3/2) cup (3/2;5)")
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